Two objects, with masses m1 and m2 , are originally a distance r apart. The magnitude of the gravitational between is F. The masses are changed to 2m1 and 2m2 , and the distance is changed to 4r. What is the magnitude of the new gravitational force?

According to Newton's gravitational law, the magnitude of the gravitational force is:

In this case, we have:

Therefore, replacing this values and solving for F' in function of F:

F

Newton's law of gravitation states that the force, F, that exists between the two objects of masses m₁ and m₂ is directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance, r, between the bodies. i.e

F ∝ (m₁m₂ / r²)

F = Gm₁m₂/r²           ------------------(i)

Where;

G = proportionality constant called the gravitational constant.

Now, when the masses are changed to 2m₁ and 2m₂, and the distance is changed to 4r, then according to equation (i) the new force (say F₂) becomes;

F₂ = G (2m₁)(2m₂) / (4r)²

F₂ = 4Gm₁m₂ / 16r²

F₂ = Gm₁m₂ / 4r²

F₂ = Gm₁m₂/r²     -------------------------(ii)

Comparing equations (i) and (ii), equation (ii) can be re-written as;

F₂ = F

Therefore, the magnitude of the new gravitational force is a quarter of the old gravitational force, F. i.e   F

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when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27