A traveling sinusoidal electromagnetic wave in vacuum has an electric field amplitude of 83.7 V/m. Find the intensity of this wave and calculate the energy flowing during 15.5 s through an area of 0.0225 m2 that is perpendicular to the wave\'s direction of propagation.

Answer with Explanation:

We are given that

Electric field,E=83.7V/m

Time,t=15.5 s

Area,A=

We have to find the intensity of the wave and energy .

Intensity,I=

Where

Substitute the values

Energy,

Substitute the values

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