You short-circuit a 9 volt battery by connecting a short wire from one end of the battery to the other end. If the current in the short circuit is measured to be 16 amperes, what is the internal resistance of the battery?

The internal resistance of the battery is 0.562 ohms.

Explanation:

Given that,

Voltage of battery, V = 9 volts

Current in the short circuit, I = 16 A

So, we can say that, the internal resistance of the battery is given by :

So, the internal resistance of the battery is 0.562 ohms.

we need to know the time interval during which the force acts. impulse of force = momentum change

c) up

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