A 0.140-kg baseball is dropped and reaches a speed of 1.20 m/s just before it hits the ground and bounces. It rebounds with an upward velocity of 1.00 m/s. What is the change of the ball's momentum during the bounce

The change of ball's momentum is 0.308

Explanation:

Given:

Mass of baseball m

Downward velocity

Upward velocity

Here we have to find change in momentum,

Momentum is given by,

Downward momentum is given by

Upward momentum is given by,

So change of the ball's momentum is given by,

Therefore, the change of ball's momentum is 0.308

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2