A 28.6-kg sled is being pulled across a horizontal surface at a constant velocity. The pulling force has a magnitude of 77.3 N and is directed at an angle of 24 ° above the horizontal. Determine the coefficient of kinetic friction.

0.3

Explanation:

Coefficient of kinetic friction= frictional force /Normal reaction

normal reaction= mgcosA

m= mass=28.6kg

g =9.8m/s and A is angle 24°

Normy reaction= 28.6*9.8cos24=256N

Frictional force =77.3N

Coefficient of kinetic friction= 77.3/256=0.3

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015