Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal polarizing filter whose axis is at 45.0 ∘∘ to that of the first. Part A Determine the intensity of the beam after it has passed through the second polarizer. Enter the factor only. For example, enter 0.2500.250, that means your answer is I=0.250I0I=0.250I0. II = nothing I0I0 SubmitRequest Answer Part B Determine its state of polarization. Determine its state of polarization. The light is linearly polarized along the axis of the first filter. The light is linearly polarized along the axis of the second filter. The light is linearly polarized perpendicular to the axis of the second filter. The light is linearly polarized perpendicular to the axis of the first filter. SubmitRequest Answer Provide Feedback

A) I = Io 0.578,   B) he light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

Explanation:

A) Light passing through a polarizer must comply with the / bad law

          I = Io cos2 tea

Where is at the angle of the polarizer and incident light

          I = Io cos2 45

         I = Io 0.578

Therefore the beam intensity is 0.578 of the incident intensity

.B) the light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

if the thermos has a vacuum innner, then heat through conv currents and conduction are reduced = vacuum flask

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.