An astronaut on a strange new planet finds that she can jump up to a height of 72 m before she would fall back down to the surface when her initial speed is 60.0 m/s What is the magnitude of the acceleration due to gravity on the planet

25m/s²

Explanation:

Using one of the equations of motion.

v² = u²+2as where

v is the final velocity of the astronaut

u is his initial velocity

a = -g (the acceleration will be acceleration due to gravity since he is acting under the influence of gravity. The value is negative because the astronaut jumps up to a particular height)

s = H = total height covered

The equation will then become;

v² = u²-2gH

Given

u = 60m/s

v = 0m/s

g = ?

H = 72m

Substituting the given value into the equation;

0² = 60²-2g(72)

0 = 3600-144g

-3600 = -144g

g = -3600/-144

g = 25m/s²

The magnitude of his acceleration due to gravity on the planet is 25m/s²

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