Meteorite On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, creating a dent about 22 cm deep. If the initial speed of the meteorite was 550 m/s, what was the average force exerted on the meteorite by the car?

8427375 N

Explanation:

From newton's equation of motion,

F = ma Equation 1

Where F = average force exerted on the meteorite by the car, m = mass of the meteorite, a = acceleration.

We can find the value of acceleration from newton's equation of motion

using,

v² = u²+2as Equation 2

Where v = final velocity, u = initial velocity, a = acceleration, s = distance.

Make a the subject of the equation

a = (v²-u²)/2s Equation 3

Note: When the meteorite struck the car, it was brought to rest

Given: u = 550 m/s, v = 0 m/s ( brought to rest), s = 22 cm = 0.22 m

Substitute into equation 3

a = (0²-550²)/(2×0.22)

a = -302500/0.44

a = -687500 m/s²

Also given: m = 27 pound = (27×0.454) = 12.258 kg

Substitute into equation 1

F = 12.258(-687500)

F = -8427375 N

Note: The negative sign tells that the force act in opposite direction to the motion of the meteorite

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

the part of the wave he is travelling on is the crest