A circular coil has a 7.85 cm radius and consists of 36.0 closely wound turns of wire. An externally produced magnetic field of magnitude 2.95 mT is perpendicular to the coil. (a) If no current is in the coil, what magnetic flux links its turns

Φ = 2.06×10^-3weber

Explanation:

Magnetic flux density is the ratio of the flux links to the area of the coil.

This can be expressed as

B =Φ/NA where:

Φ is the magnetic flux

B is the magnetic field strength

A is the area of the coil.

N is the number of turn in the wire

Given

B = 2.95 mT = 2.95×10^-3T

N = 36

radius = 7.85cm = 0.0785m

A = πr² ( since it is a circular coil)

A = π(0.0785)²

A = 0.0194m²

From the formula Φ = BAN

Φ = 2.95×10^-3 × 0.0194×36

Φ = 2.06×10^-3weber

an electric circuit

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