A 200-mm lever and a 240-mm-diameter pulley are welded to the axle BE that is supported by bearings at C and D. A 860-N vertical load is applied at A when the lever is horizontal. Assume that the bearing at D does not exert any axial thrust.

A 200mm lever and a 240 mm diameter pulley are welded to the axle BE that is supported by bearings at C and D. If a 860N vertical load is applied at A when the lever is horizontal, determine (a)the tension in the cord, (b)the reactions at C and D. assume that the bearing at D does not exert axial thrust.

see explanation

Explanation:

Part a

The tension in the cord

860(200) - T(120) = 0

T(120) = 172000

T =1433.33N

The tension in the cord (T) = 1433.33N

Part b

Apply the moment law of equilibrium at point D about y-axis.

sustitute 1433.33N for T

The reaction at C along x-axis 477.78N

Apply the moment law of equilibrium at point D about x-axis

The reaction at C along y-axis is 143.33N

Apply the force law of equilibrium along z direction.

The reaction at C along z-axis is 0N

Apply the force law of equilibrium along x direction.

substitute 477.78N  for and 143.33N for

The reaction at D along x-axis is -1911.11 N

Apply the force law of equilibrium along y direction.

substitute 1433.33 for

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )