An air-track glider attached to a spring oscillates between the 13.0 cm mark and the 65.0 cm mark on the track. The glider completes 14.0 oscillations in 35.0 s . What are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider?

Time period = 2.5 sec

Frequency = 0.4 Hz

Amplitude =  0.26 m

Maximum speed = 0.65

Explanation:

No. of oscillations = 14

Time = 35 sec

(a). Time period of oscillation

T = 2.5 sec

This is the time period.

(b). Frequency

f = 0.4 Hz

This is the  frequency.

(c). Oscillation from one side to another side is 65 - 13 = 52 cm = 0.52 m

Hence amplitude

A = 0.26 m

This is the amplitude.

(d). The maximum speed

2 × 3.14 × 0.4 × 0.26

0.65

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.