Ask Your Teacher A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 33.5° and the angle of refraction is 19.3°, find the critical angle for the liquid when surrounded by air.

The critical angle for the liquid when surrounded by air is 30 degrees.      

Explanation:

Given that,

The angle of incidence is 33.5° and the angle of refraction is 19.3°. Firstly, we can find the refractive index of the liquid. It can be calculated using Snell's law as :

The critical angle is given by :

Here, is refractive index of air and is refractive index of liquid.

So, the critical angle for the liquid when surrounded by air is 30 degrees.

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  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.