A loop antenna of area A = 3.25 cm2 and resistance R = 7.17 μΩ is perpendicular to a uniform magnetic field of magnitude 20.2 μT. The field magnitude drops to zero in 2.03 ms. How much thermal energy is produced in joules in the loop by the change in field?

Explanation:

change in flux = area x change in magnetic field

= 3.25 x 10⁻⁴  x ( 20.2 - 0 ) x 10⁻⁶

= 65.65 x 10⁻¹⁰ Weber .

emf induced = change in flux / time

= 65.65 x 10⁻¹⁰ / 2.03 x 10⁻³

= 32.34 x 10⁻⁷ V

current = volt induced / resistance

= 32.34 x 10⁻⁷ / 7.17 x 10⁻⁶

= .451 A

Thermal energy produced = I²R t , I is current , R is resistance , t is time

= .451² x 7.17 x 10⁻⁶ x 2 .03 x 10⁻³

= 2.96 x 10⁻⁹ J .

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information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

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we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer