Two particles with charges of 2nC and 5nC are separated by a distance of 3m. The charge 2nC is placed on the left. Find the force on charge 2nC

to the left

Explanation:

The magnitude of the electrostatic force between two charges is given by the following equation:

where:

is the Coulomb's constant

are the magnitude of the two charges

r is the distance between the two charges

Moreover, the force is:

- Attractive if the charges have opposite sign

- Repulsive if the charges have same sign

In this problem, we have:

is the magnitude of charge 1

is the magnitude of charge 2

r = 3 m is the distance between the two charges

Substituting, we find the force on both charges:

Here, the two charges are both positive, so the force is repulsive; since the 2 nC charge is on the left, this means that the force on this charge is to the left (away from the 5 nC charge).

c

explanation:

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete