The water level in a tank is 20 m above the ground. a hose is connected to the bottom of the tank, and the nozzle at the end of the hose is pointed straight up. the tank is at sea level, and the water surface is open to the atmosphere. in the line leading from the tank to the nozzle is a pump, which increases the pressure of water. if the water jet rises to a height of 30 m from the ground, determine the minimum pressure rise supplied by the pump to the water line. take the density of water to be rho = 1000 kg/m3.

P_(pump) = 98,000 Pa

Explanation:

We are given;

h2 = 30m

h1 = 20m

Density; ρ = 1000 kg/m³

First of all, we know that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,

Thus, it can be expressed as;

P_(tank)+ P_(pump) = P_(nozzle)

Now, the pressure would be given by;

P = ρgh

So,

ρgh_1 + P_(pump) = ρgh_2

Thus,

P_(pump) = ρg(h_2 - h_1)

Plugging in the relevant values to obtain;

P_(pump) = 1000•9.8(30 - 20)

P_(pump) = 98,000 Pa

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