Two identical 2.55 x 10^-4 c charges are held 0.500 m apart. the second one is released. when it reaches a distance of 2.15 m from the other charge, how much has the electric potential energy changed
(unit=j)

-898.3 J

Explanation:

The electric potential energy of a system of two charges is given by

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the two charges

In this problem, at the beginning we have:

are the two charges

is the initial separation

While after the charges have been released, we have:

is the final distance

Therefore, the change in electric potential energy is:

i would say

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