The table lists the range of wavelengths in vacuum corresponding to a given color. If light one illuminates a film that has a refractive index of 1.333 and thickness of 183 nm with white light, which color is missing from the light reflected from the film?Color Wavelength (nm)red 780 - 622orange 622 - 597yellow 597 - 577green 577 - 492blue 492 - 455violet 455 - 390
A) redB) yellowC) blueD) greenE) orange

please see the answer below

Explanation:

we can use the following expression:

where lambda is the wavelength of the light, n is the refractive index of the film, d is the thickens of the film and m is the order of the diffraction pattern. If m=1, we obtain the max value of lambda for the colors that are reflected.

Hence, we have:

for m=1 487.878nm is the more reflected light. Hence, all colors with wavelength below this values are not reflected.

the following are colors that are not reflected

- 780nm red

- 622nm orange

- 597nm yellow

- 577nm greeen

- 492nm blue

hope this helps!

The missing color from the light reflected is the blue.

Explanation:

The wavelength of the light is equal to:

Where

n = refractive index = 1.333

d = thickness = 183 nm

Replacing:

This value is between 455 to 492 nm (blue)

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.