A 2 kg book is pushed from rest to a final velocity of 3 m/s. The book travels 2 m. How much force was the book pushed with

Explanation:

first you have to find accelerarion, it is given that the initial velocity(u) is 3 m/s, distance travelled(s) be 2m finall it came to rest so final velocity be 0m/s

now using the 3rd law of motion

v^2=u^2+2as

0=9+2a2

a= -9/4m/s^2

now force=mass×accelration

=2kg×(-9/4)m/s^2

=4.5 N

4.5 newton force applied on the book!

✌️:)

4.5N

Explanation:

Step 1:

Data obtained from the question:

Mass (m) = 2Kg

Initial velocity (U) = 0

Final Velocity (V) = 3m/s

Distance travelled (s) = 2m

Force (F) =?

Step 2:

Determination of the acceleration of the book. This is illustrated below:

Using V^2 = U^2 + 2as, the acceleration (a) can be obtained as follow:

V^2 = U^2 + 2as

3^2 = 0 + 2 x a x 2

9 = 4a

Divide both side by the coefficient of a i.e 4

a = 9/4

a = 2.25m/s2

Step 3:

Determination of the force applied. This is illustrated below:

Force = Mass x Acceleration

F = m x a

F = 2 x 2.25

F = 4.5N

Therefore, a force of 4.5N was used to push the book.

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles