A worker pushes horizontally on a 36.0 kg crate with a force of magnitude 112 N. The coefficient of static friction between the crate and the floor is 0.380. (a) What is the value of fs, max under the circumstances

value of fs,max under the circumstances is

f = 42.56 N

Explanation:

The formula is µ = f / N, where µ is the coefficient of friction, f is the amount of force that resists motion, and N is the normal force. Normal force is the force at which one surface is being pushed into another.

So f = µN

f = 0.380 * 112

f = 42.56 N

i think it would be 80 km/h because 30 + 50 = 80 (sorry if this not the right answer i'm trying my best)