An electron and a second particle both move in circles perpendicular to a uniformmagnetic field. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton. If both of time to go once around their respective circles, determine the charge of thissecond particle. You may use the values:melectron9.1110−31kg, qelectron1.6010−19C, andmproton1.6710−27kg.

The change on the second particle is .

Explanation:

The period of revolution of the particle in the magnetic field is given by the formula as follows :

It is given that the magnetic field is uniform. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton.

If both particles take the same amount of time to go once around their respective circles. So,

So, the change on the second particle is .

force tends to be low and long diustance masses are high

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m