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Physics, 14.04.2020 17:36 deonceee4671

You can check your result by comparing its magnitude to the magnitude the acceleration would have if the particle's velocity had the same magnitude but it was perpendicular to the magnetic field. Find the value of the expression qvB/m (the magnitude of a⃗ when v⃗ is perpendicular to B⃗ ), where q is the magnitude of the charge, v is the magnitude of the velocity, B is the magnitude of the magnetic field, and m is the mass of the particle. Express your answer in meters per second squared.

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