A golfer strikes a stationary golf ball that has a mass of 0.02 kg. The golf ball leaves the club with a speed of 180 m/s. A high-speed camera determines that the club was in contact with the ball for 0.56 x 10-3 s . What was the average force applied by the club to the ball in newtons

Answer

The average force applied by the club to the ball in Newtons is 6428.5N

Explanation:

Step one :

Given data

Mass of golf ball =0.02kg

Velocity of the ball= 180m/s

Time =0.56*10-³s

Step two :

We know that the impulse equation is given by

P*t=m*v

Where p= impulse in Newton?

t=time in seconds

m= mass in kg

v= velocity in m/s

Step three

To find the average force applied we Substitute our data into the equation we have

P*0.56*10-³=0.02*180

P=3.6/0.56*10-³

P=6428.5N

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answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.