A 4.00 kg mass is moving at 4.00 m/s 45.0 degrees NORTH of WEST and a 6.00 kg mass is moving at 3.00 m/s 30.0 degrees SOUTH of EAST. Find the velocity of the center of mass, letting (a) = the east-west component, and (b) = the north-south component.

(a) 0.428 m/s

(b) 0.232 m/s

Explanation:

mass, m = 4 kg

initial velocity, u = 4 m/s at 45° North of west = 4 ( - Cos 45 i + Sin 45 j)

mass, M = 6 kg

initial velocity, U = 3 m/s at 30° South of east = 3 (Cos 30 i - Sin 30 j)

Let V is the velocity of centre of mass.

(a)

east west component of velocity of centre of mass is 0.428 m/s

(b)

north south component of velocity of centre of mass is 0.232 m/s.

Explanation:

b

explanation:

bc its just b

newton's first law of motion