A stone with a mass of 0.70 kg is attached to one end of a string 0.80 m long. The string will break if its tension exceeds 65.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed. Find the maximum speed the stone can attain without breaking the string.

The maximum speed the stone can attain without breaking the string is 8.62 m/s .

Explanation:

Given :

Mass of stone , m = 0.7 kg .

Length of string , l = 0.8 m .

It is also given that the stone will break if its tension exceeds 65.0 N.

Now , we know tension in the rope due to rotation is equal to the centripetal acceleration .

Therefore , the maximum speed the stone can attain without breaking the string is less than or equal to 65 N .

So ,

Putting all value in above equation we get :

Therefore , maximum speed the stone can attain without breaking the string is 8.62 m/s .

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//