A spring stretches by 0.0173 m when a 2.62-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.0 Hz?

Answer

4.16kg mass should be added

Explanation:

Step one :

Given

Extention e=0.0173m

Suspended Mass m=2.62kg

Frequency f=3hz

But F=ma

F=2.62*9.81

F=25.6N

Step two

Applying the hooks law equation

F=ke

Where k is the spring constant

k=F/e

k=25.6/0.0173

k=1480N/m

Step three

To solve for the additional mass that causes a frequency of vibration of 3hz

m=k/4*pi²*f²

Substituting our values into the equation we have

m=1480/4*3.142²*3²

m=1480/355.4

m=4.16kg

he kicked it 10 feet straight up into the air? i think this works.

c)as speed changes, wavelength and frequency change.

everything changes!