If 61.4 cm of copper wire (diameter = 1.08 mm, resistivity = 1.69 × 10-8Ω·m) is formed into a circular loop and placed perpendicular to a uniform magnetic field that is increasing at the constant rate of 9.14 mT/s, at what rate is thermal energy generated in the loop? Number Enter your answer in accordance to the question statement Units Choose the answer from the menu in accordance to the question statement

the thermal energy generated in the loop =

Explanation:

Given that;

The length of the copper wire L = 0.614 m

Radius of the loop  r =

r =

r = 0.0977 m

However , the area of the loop is :

Change in the magnetic field is

Then the induced emf e =

e =

e = 2.74 × 10⁻³ V

resistivity of the copper wire Ω m

diameter of the wire = 1.08 mm

radius of the wire = 0.54 mm = 0.54 × 10⁻³  m

Thus, the resistance of the wire  R =

R =  

R = 1.13× 10⁻² Ω

Finally,  the thermal energy generated in the loop (i.e the power) =

=

=

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.

in physics zero. in muscle fatigue could be high