A person of mass 80 kg stands at the center of a rotating merry-go-round platform of radius 3.5 m and moment of inertia 950 kg*m^2 . The platform rotates without friction with angular velocity 0.85 rad/s . The person walks radially to the edge of the platform.
1. Calculate the angular velocity when the person reaches the edge.
w= rad/s
2. Calculate the rotational kinetic energy of the system of platform plus person before the person's walk.
Ki= J
3. Calculate the rotational kinetic energy of the system of platform plus person after the person's walk.
Kf= J

Answer with Explanation:

We are given that

Mass of person,M=80 kg

Radius,r=3.5 m

Moment of inertia of merry,I=

Angular velocity of platform=

1.Law of conservation of angular momentum

Where

Substitute the values

Angular velocity when the person reaches the edge =0.418 rad/s

2.Rotational kinetic energy of the system  before the person's walk

3.Rotational kinetic energy of the system  after the person's walk

a. carbon monoxide from car exhaust

b.particulate matter, such as soot

c.water vapor from a factory smokestack

d.acid rain

these are the answer choices im on that question right now