In two-photon ionization spectroscopy, the combined energy of two different photons is used to remove an electron from an atom or molecule. In such an experiment, a potassium atom in the gas phase is ionized by two different lasers, one of which has a wavelength of 770.0 nm. What is the maximum wavelength for the second laser that will cause two-photon ionization? The ionization energy of potassium is 6.96E-19 J. nm

The maximum wavelength of second laser is 453.8 nm

Explanation:

Given:

Wavelength of light m

Ionization energy of potassium J

First find the energy related to the one of light,

Where ,

    J

This is the energy of the first laser, the missing energy is given by.

   J

For finding wavelength of second laser,

    m

    nm

Therefore, the maximum wavelength of second laser is 453.8 nm

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