A 35.2-g sample of an alloy at 93.0°C is placed into 219 g of water at 22.0°C in an insulated coffee cup. Assume that no heat is absorbed by the cup. If the final temperature of the system is 31.1°C, what is the specific heat capacity of the alloy in J/(g. K)? Don't include units. cH2O = 4.184 J/g. K

Explanation:

mass of the alloy = 35.2 g

temperature t of the alloy = 93° C

heat loss by alloy = mc ( t₁ - t₂) where t₁ = 93 and t₂ = 31.1° C

heat loss by alloy = 2178.88 c where c is the specific heat capacity of the alloy

heat gained by water = m cw ( t₂ - t₁ ) where t₁ of water = 22° C and t₂ of water = 31.1° C

heat gained by water = 8338.294

heat gained = heat loss

2171.84 c =  8338.294

c specific heat capacity of the alloy = 8338.294 / 2178.88 = 3.83 J/g.K

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation: