A 24.0 g marble moving to the right at 23.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same direction at 20.0 cm/s. After the collision, the 10.0 g marble moves to the right at 22.5 cm/s. Find the velocity of the 24.0 g marble after the collision. cm/s to the right?

The final speed of the 24 g marble after the collision is 0.21 m/s.

Explanation:

Given that,

Mass of the marble 1, m = 24 g = 0.024 kg

Initial speed of the marble 1, u = 23 cm/s = 0.23 m/s

Mass of the marble 2, m' = 10 g = 0.01 kg

Initial speed of the marble 2, u' = 20 cm/s = 0.2 m/s

After the collision,

Final speed of marble 2, v' = 22.5 cm/s = 0.225 m/s                        

We need to find the velocity of the 24.0 g marble after the collision. It is a case of elastic collision. Using the conservation of momentum as :

v is the speed of  24.0 g marble after the collision.

So, the final speed of the 24 g marble after the collision is 0.21 m/s.

protons in

weather forecasts are done by collecting data about the current state of the atmosphere mainly the temperature, humidity and wind and using meteorology, to determine the atmosphere that evolves over time. the h and l mean the high and low pressure. the red strip is a warm front. the blue strip is a cold front. the blue and red strip is a stationary front. the purple strip is a occluded front.

explanation: