A 0.42-kg block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so that the spring stretches for 2.1 cm relative to its unstrained length. When the block is released, it moves with an acceleration of 9.0 m/s2. What is the spring constant of the spring?

The spring constant of the spring is 180 N/m.

Explanation:

It is given that,

Mass of the block, m = 0.42 kg

The block is pulled so that the spring stretches for 2.1 cm relative to its unstained length.

When the block is released, it moves with an acceleration of . We need to find the spring constant of the spring. For a block to be in equilibrium, the net force is given by :

k is spring constant of the spring

So, the spring constant of the spring is 180 N/m.

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..