The work function of a certain metal is 6.6 eV. When a photon whose frequency is 2.80 x 1015 Hz is absorbed by an electron below the surface, the electron escapes the surface with 3.5 eV of kinetic energy. How much energy (in eV) did the electron use to reach the surface

The energy used to reach the surface is 1.53 eV.

Explanation:

Given that, the work function of a certain metal is 6.6 eV.

Frequency of photon,

Kinetic energy of the electron,

The energy of the photon is:

Energy utilized by the photon is given by :

Used energy is given by the difference of energy given and the energy utilized. So,

So, energy used to reach the surface is 1.53 eV.

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.