Two identical traveling waves, moving in the same direction, are out of phase by π/5.0 rad. What is the amplitude of the resultant wave in terms of the common amplitude ym of the two combining waves? (Give the answer as the ratio of the total amplitude to the common amplitude.)

Explanation:

amplitude of the resultant wave is ytotal is 1.902 times common amplitude

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Therefore the amplitude of the resultant wave is

Explanation:

The equation of wave:

y=A sin (kx-ωt)

For wave 1:

y₁=A sin (kx-ωt) = sin (kx-ωt)

For wave 2:

y₂=A sin (kx-ωt+Φ) = sin (kx-ωt+Φ)

Where A= amplitude=

The angular frequency

, = wave length.

t= time

T= Time period

= phase difference =  

The resultant wave will be

y = y₁ + y₂

 = sin (kx-ωt) + sin (kx-ωt+Φ)

  {sin (kx-ωt) + sin (kx-ωt+Φ)}

Therefore the amplitude of the resultant wave is

a

explanation:

because they are cartillidge

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.