A small wooden block with mass 0.750 kg is suspended from the lower end of a light cord that is 1.72 m long. The block is initially at rest. A bullet with mass 0.0100 kg is fired at the block with a horizontal velocity v0. The bullet strikes the block and becomes embedded in it. After the collision the combined object swings on the end of the cord. When the block has risen a vertical height of 0.800 m, the tension in the cord is 4.86 N.
What was the initial speed v0 of the bullet?

Explanation:

We need to use the momentum and energy conservation.

Where:

Conservation of energy.

We have kinetic energy at first and kinetic and potential energy at the end.            

Here:

We can find V(2) using the definition of force at this point:

Now, we can solve the equation to find V(2)

Now we can find V(1) using the conservation of energy equation

Finally, using the momentum equation we find v(0)

I hope it helps you!

i don't understand. explain it clearly

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.