An 8.00-cm-long piece of wire is formed into a square, and carries a clockwise current of 0.150 A. The loop is placed inside a solenoid, and the plane of the loop is perpendicular to the solenoid’s magnetic field. The solenoid carries a counterclockwise current of 17.0 A, and has 25 turns per centimeter. What is the force on each side of the loop?

A) 6.41E–4 N
B) 1.60E–4 N
C) 1.07E–5 N
D) 4.27E–3 N

Force on wire is

Explanation:

We have given length of wire l = 8 cm = 0.08 m

Current in the wire i = 0.150 A

Number of turns in solenoid

Magnetic field due to solenoid

Now magnetic force on the wire

So force on wire is

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f=ma newton's second law 7x8=56n