An incredible amount of electrical energy passes down the funnel of a large tornado every second. Measurements at a distance of 12.8 km from a large tornado showed an almost constant magnetic field of 2.35 × 10−8 T associated with the tornado. What was the average current going down the funnel? (µ0 = 4π × 10−7 T⋅m/A)

The average current going down the funnel is 1504 A.

Explanation:

Given that,

Magnetic field,

Measurements at a distance of 12.8 km from a large tornado, r = 12.8 km

We need to find the average current going down the funnel. We know that the magnetic field due to current carrying conductor is given by :

I is current

So, the average current going down the funnel is 1504 A. Hence, this is the required solution.

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explanation: