A small planet having a radius of 1000 km exerts a gravitational force of 100 N on an object that is 500 km above its surface. If this object is moved 500 km farther from the planet, the gravitational force on it will be

56.25 N

Explanation:

Given,

Radius of the planet, r = 1000 km

Gravitational force, F = 100 N

Initial distance from the planet, d = 500 km

Final distance from the planet, D = 1000 km

Lets assume, mass of planet = M

mass of the object = m.

As per the gravitational law, the force due to gravity is given as

where, G = gravitational constant

R =  distance between the two objects.

Case 1: when the object is at a distance of 500 km from the planet,

Here, R = 1000 + 500 = 1500 km, so

Case 2: when the object is at a distance of 1000 km from the planet, so

now, R = 1000 + 1000 = 2000 km

Now the gravitational force, F' will be

Thus, the gravitational force will now be reduced to 56.25 N.

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement