A pump is partially submerged in oil and is supported by 4 springs. The oil has a specific gravity of 0.90, the weight of the pump is 14.6 lb, and the submerged volume is 40 in3. What force is needed in the springs so that the pump will remain in static equilibrium

Explanation:

submerged volume of pump = 40 x 12⁻³ ft³

density of oil = .9 x 62.4 lb ft⁻³ ( specific gravity x density of water )

mass of displaced oil = 40 x 12⁻³ x  .9 x 62.4 lb

= 1.3 lb

buoyant force = 1.3 lb

weight of pump = 14.6 lb

extra force needed for balancing pump by spring

= 14.6 - 1.3

= 13.3 lb .

you cant move and you feel like someones pushing you down onto your bed it can feel like you want to get up but you just can't it can be extremely scary

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west