The only force acting on a 3.1 kg canister that is moving in an xy plane has a magnitude of 2.6 N. The canister initially has a velocity of 2.3 m/s in the positive x direction, and some time later has a velocity of 6.4 m/s in the positive y direction. How much work is done on the canister by the 2.6 N force during this time?

55.29 J

Explanation:

mass of canister, m = 3.1 kg

magnitude of force, F = 2.6 N

initial velocity, u = 2.3 m/s

final velocity, v = 6.4 m/s

Let W is the work done.

According to the work energy theorem, the work done by all forces is equal to he change in kinetic energy.

here F is the only force acting on the canister.

initial kinetic energy, k = 0.5 x m x u²

k = 0.5 x 3.1 x 2.3 x 2.3 = 8.1995 J

final kinetic energy, k' = 0.5 x m x v²

k' = 0.5 x 3.1 x 6.4 x 6.4 = 63.488 J

So, the change in  kinetic energy,

Δk = k' - k

Δk = 63.488 - 8.1995 = 55.29 J

Thus, the work done by the force is 55.29 J.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

answer: a. same unit

explanation: