A hollow, conducting sphere with an outer radius of 0.257 m and an inner radius of 0.203m has a uniform surface charge density of +6.31×10−6C/m^2 . A charge of -0.870uC is now introduced into the cavity inside the sphere.

A)What is the new charge density on the outside of the sphere?

B)Calculate the strength of the electric field just outside the sphere.

C)What is the electric flux through a spherical surface just inside the inner surface of the sphere?

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.