Toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of .2kg and the robot has a mass of .3 KG. The robot pushes on the door with a force of .3 N. The magnitude of the acceleration of the robot is

The magnitude of the acceleration of the robot is 1 m/s²

The given parameters;

mass of the toy doll, m = 0.2 kg

mass of the robot, M = 0.3 kg

force applied by the robot, F = 0.3 N

The magnitude of the acceleration of the robot is calculated from Newton's second law of motion;

F = ma

where;

a is the acceleration of the robot

Thus, the magnitude of the acceleration of the robot is 1 m/s²

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because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

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