A 3.70-mm-long, 520 kgkg steel beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 73.0 kgkg construction worker stands at the far end of the beam. What is the magnitude of the torque about the point where the beamis bolted into place?

the magnitude of the torque about the point where the beam is bolted into place 12.32kNm

Explanation:

N/B The units given in the question are meant to be m, kg and kg respectively

Given data

Length of beam 3.7m

Mass of beam 520kg

Mass of construction worker 73kg

Torque is expressed as the moment or turning effect brought about by a couple

T= F*d

Where d=perpendicular distance

F= force

Converting The mass of the beam and the worker to force we have

520*10= 5200N

73*10=730N

Note that the force due to the mass of the beam is acting at the center of the beam

See the free body diagram attached

Taking moments about point O

Torque =Σ Fxd

Torque =5200x1.85+7x3.7

=9620+2701

=12321 Nm

=12.32kNm

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get