The centripetal acceleration might better be expressed as −ω2r⃗ (t)−ω2r→(t) because it is a vector. The magnitude of the centripetal acceleration is v2radial/Rvradial2/R. The magnitude of the centripetal acceleration is v2tangential/Rvtangential2/R. A particle that is going along a path with local radius of curvature RRR at speed sss experiences a centripetal acceleration −s2/R−s2/R. If you are in a car turning left, the force you feel pushing you to the right is the force that causes the centripetal acceleration. In these statements vradialvradialv_radial refers to the component of the velocity of an object in the direction toward or away from the origin of the coordinate system or the rotation axis. Conversely, vtangentialvtangentialv_tangential refers to the component of the velocity perpendicular to vradialvradialv_radial. Identify the statement or statements that are false.

false  b) a = v²(radial) / r  and e)

Explanation:

Let's review given statement separately

a) centripetal acceleration

       a = v² / r

linear and angular velocity are related

     v = w r

we substitute

       a = w²r

this acceleration is directed to the center of the circle, so the vector must be negative

        a = - w r2

the bold are vector

True this statement

b) the magnitude is the scalar value

     a = v² / r

where v is the tangential velocity, not the radial velocity, so this statement is

False

c) This is true

      a = v²/ r

this speed is tangential

d) Newton's second law is

         F = m a

if the acceleration is centripetal

         F = m (- v² / r)

we substitute

         F = m (- s² / R)

the statement is true

e) when the car turns to the left, the objects have to follow in a straight line, which is why

you need a force toward the center of the circle to take the curve.

     Consequently there is no outward force

This statement is false

we need to know the time interval during which the force acts. impulse of force = momentum change