To verify her suspicion that a rock specimen is hollow, a geologist weighs the specimen in air and in water. She finds that the specimen weighs twice as much in air as it does in water. The density of the solid part of the specimen is 5.0×103kg/m35.0×10
3
kg/m
3
. What fraction of the specimen's apparent volume is solid?

Fraction of the specimen's is 0.4.

Explanation:

We know,

Mass = volume × density

Weigh= mass × g

          = volume × density× g

          = density× g × volume

An object weighs less submerged due to buoyant force acting on it.

Given that, the weighs of the specimen in dry is twice of the weighs in air.

Then ,

Therefore,

                     =0.4

Fraction of the specimen's is 0.4.

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m