A 0.250 kg block on a vertical spring with a spring constant of 5.00 x 103 N/m is pushed downward compressing the spring 0.100 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above its point of release

The height at point of release is 10.20 m

Explanation:

Given:

Spring constant

Compression m

Mass of block kg

Here spring potential energy converted into potential energy,

For finding at what height it rise,

                 ( ∵ )

  m

Therefore, the height at point of release is 10.20 m

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.