The generator at a power plant produces AC at 20,000 V. A transformer steps this up to 355,000 V for transmission over power lines. If there are 2,250 turns of wire in the input coil of the transformer, how many turns must there be in the output coil

Number of coil in the output is 39938

Explanation:

We have given a step up transformer

Input voltage of transformer, that is primary voltage

Output voltage, that is secondary voltage

Number of turns in primary

For transformer we know that

As the number of turns can not be in fraction so number of turns in the output coil is 39938

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s