We are going to make an imaginary engine using water. We are going to heat 100 grams of water to 120 C from its initial temperature of 22 C. This would be the heat extracted from the hot reservoir. Then the steam will condense back into water and will be at a temperature of 30 C. This would be the exhaust expelled into the cold reservoir. You can assume the mass of the water and the mass of the steam is the same in this case. How much work can be done using this engine? The specific heat of water is 1 cal/(g C), the specific heat of steam is 0.48 cal/(g C),
and the latent heat of vaporization 540 cal/g.

The work done by this engine is 800 cal

Explanation:

Given:

100 g of water

120°C final temperature

22°C initial temperature

30°C is the temperature of condensed steam

Cw = specific heat of water = 1 cal/g °C

Cg = specific heat of steam = 0.48 cal/g °C

Lw = latent heat of vaporization = 540 cal/g

Question: How much work can be done using this engine, W = ?

First, you need to calculate the heat that it is necessary to change water to steam:

Here, mw is the mass of water

Now, you need to calculate the heat released by the steam:

The work done by this engine is the difference between both heats:

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.

the answer would most likely be c, because if it's a comical piece of information, it may likely not be true, if it's a site that allows anybody to edit the content, it could mean a five year old is typing the info, and if it's a tv show produced by a celeb, it may have a biased opinion.