A dragster accelerated to a speed of 112m/s over a distance of 398m. Determine the acceleration (assume uniform) of the dragster.

. Given- vf-112m/s, d-398m, Vi-0m/s (112 m/s)2 =

(0 m/s)2 + 2*(a)*(398 m)12544 m2/s2 = 0 m2/s2 + (796 m)*a12544 m2/s2 =

(796 m)*a(12544 m2/s2)/(796 m) = aa = 15.8 m/s26.

luster is not a good characteristic to use by itself because luster is the property of minerals that indicates how much the surface of a mineral reflects light. the luster of a mineral is affected by the brilliance of the light used to observe the mineral surface.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.