: Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at sea level. One container is in Denver at an altitude of about 6,000 ft and the other is in New Orleans (at sea level). The surface area of the container lid is 4 -0.0155 m. The air pressure in Denver is PD - 79000 Pa. and in New Orleans is Pro=100250 Pa. Assume the lid is weightless.

Part (a) Write an expression for the force FNo required to remove the container lid in New Orleans.
Part (b) Calculate the force Fno required to lift off the container lid in New Orleans, in newtons.
Part (c) Calculate the force Fp required to lift off the container lid in Denver, in newtons.
Part (d) is more force required to lift the lid in Denver (higher altitude, lower pressure) or New Orleans (lower altitude, higher pressure)?

Following are the solution to the given points:

Solution:

In Denver, the container's altitude is:

The surface of a container lid:

Its container's elevation in Orleans is now at sea level.

The air density in Denver:

The air pressure at New Orleans:

In general, force is mathematically described as

And we're told that the level within the box is half that of that at sea level, and as such, the pressure acting just on the tank would've been Its pressure at water level is steady with a value of

So that the , which is the pressure difference between the inside and outside of the vessel, is

So

Numbers are now substituted.

In Denver, there is indeed a strong campaign to remove the lid.

Therefore, we're told that its pressure within the container is twice that of at sea level, so the pressure pressing on the containers would've been equal to that. Above sea level, the pressure is indeed continuous with such a value of

Denver's air pressure at sea level is described mathematically as

Assume that h = 1 is the elevation at sea level. is the elevation of the airflow.

is an abbreviation for Rhodium Dioxide.

Considering both

Substituting a different value:

 So

So

So

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