Astudent increases the temperature of a 556 cm3 balloon from 278 k to 308 k. assuming constant pressure, what should the new volume of the view be?
320 cm3
501 cm3
1232 cm3
616 cm3

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 308 K x 556 cm³  / 278 K

V2 = 616 cm³

the assestment will probley apele with cause and effect

answer is slate

hope this